## Problem

Find for what values of natural n

the expression n^{3 }- 7 is divisible by (n-1).

No Euclidean division!

## Answer Submission Is Not Available

Form is valid through May 2018

## Solution

Dear friends and visitors of the site,

thank you for your replies to the May Problem.

The first to send a correct solution was Emmanuelle.

Congrats to her!

Here is my solution:

n^{3} -7=( n^{3} -1)- 6.

So (n-1) is a factor of 6 and is equal to 1,2,3,6.

Thus n can be equal to 2,3,4,7

Thank you again and let's try the June Problem.

Yours,

Serge Hazanov

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